tanx=-1,x属于[0,2π] x=
问题描述:
tanx=-1,x属于[0,2π] x=
答
x=2kπ-π/4
0x=π-π/4=3π/4
x=2π-π/4=7π/4
tanx=-1,x属于[0,2π] x=
x=2kπ-π/4
0x=π-π/4=3π/4
x=2π-π/4=7π/4