求由方程xsiny-ycosx=2确定的隐函数y=yx的导数dy/dx
问题描述:
求由方程xsiny-ycosx=2确定的隐函数y=yx的导数dy/dx
答
对两边求导.
xcosy×dy/dx+siny-dy/dx×cosx+ysinx=0
(xcosy-cosx)dy/dx=-siny-ysinx
所以dy/dx=(-siny-ysinx)/ ( xcosy-cosx ) .