求由方程xsiny-ycosx=2确定的隐函数y=yx的导数dy/dx

问题描述:

求由方程xsiny-ycosx=2确定的隐函数y=yx的导数dy/dx

对两边求导.
xcosy×dy/dx+siny-dy/dx×cosx+ysinx=0
(xcosy-cosx)dy/dx=-siny-ysinx
所以dy/dx=(-siny-ysinx)/ ( xcosy-cosx ) .