f(sinx)=cos2x-1,求f(cosx)
问题描述:
f(sinx)=cos2x-1,求f(cosx)
答
f(sinx)=cos2x-1( x ∈ R),cos2x = 1-2sin^2(x).(sin^2(x) = sinx * sinx )
所以f(sinx)=-2sin^2(x),
可得f(cosx) = - 2cos^2(x)