100X的平方+10(X+3)+X=202+25(X+3) 求X
问题描述:
100X的平方+10(X+3)+X=202+25(X+3) 求X
答
100X的平方+10(X+3)+X=202+25(X+3) 100x^2+10x+30+x=202+25x+75100x^2+11x-25x+30-202-75=0100x^2-24x-247=0(10x)^2 -2*10x*1.2+1.44-1.44-247=0(10x-1.2)^2=248.4410x-1.2=正负根号248.44所以x1=根号248.44+1.2,x2...