化简sin(2π-α)cos(3π+α)cos(3/2π+α)/sin(-π+α)sin(3π-α)cos(-α-π)
问题描述:
化简sin(2π-α)cos(3π+α)cos(3/2π+α)/sin(-π+α)sin(3π-α)cos(-α-π)
.
答
sin(2π-α)cos(3π+α)cos(3/2π+α)/sin(-π+α)sin(3π-α)cos(-α-π)
=(-sinα)(-cosα)sinα/(-sinα)sinα(-cosα)
=1