[ Help Me ]
问题描述:
[ Help Me ]
1.用因式分解法做.
(1)3x(x-1)+x-1=0
(2)(x-1)(x+3)=12
2.试写出一个以-1和2为两根的一元二次方程.
答
(1)3x(x-1)+x-1=0(3x+1)(x-1)=03x+1=0或x-1=0x=-1/3或x=1(2)(x-1)(x+3)=12x²+2x-3=12x²+2x-15=0(x+5)(x-3)=0x+5=0或x-3=0x=-5或x=3(3)设所求方程是x²+px+q=0由韦达定理得-1+2=-p,-1×2=q求得,p...