求值:tan(2π+π/4 )+tan(4π+π/4)+tan(6π+π/4).+tan(2010π+π/4)=

问题描述:

求值:tan(2π+π/4 )+tan(4π+π/4)+tan(6π+π/4).+tan(2010π+π/4)=

tan(2π+π/4 )+tan(4π+π/4)+tan(6π+π/4).+tan(2010π+π/4)=2010/2=1005