a^3+b^3+3a^2+3b^2+3a+3b+2=
问题描述：
a^3+b^3+3a^2+3b^2+3a+3b+2=
答
原式=(a³+3a²+3a+1)+(b³+3b²+3b+1)
=(a+1)³+(b+1)³
=[(a+1)+(b+1)][(a+1)²-(a+1)(b+1)+(b+1)²]
=(a+b+2)(a²-ab+b²+a+b+1)