计算:1\x+2-1\x-2+2\x^2-4
问题描述：
计算:1\x+2-1\x-2+2\x^2-4
要过程,麻烦各位大侠了.
最好在五分钟之内回复我！
答
=(x-2)/(x+2)(x-2) -(x+2)/(x+2)(x-2)+2/(x+2)(x-2)
=[(x-2)-(x+2)+2[/(x+2)(x-2)
=-2/(x+2)(x-2)谢谢你啊！