实数x满足log3x=1+sinθ,则|x-1|+|x-9|的值为_.
问题描述:
实数x满足log3x=1+sinθ,则|x-1|+|x-9|的值为______.
答
由于-1≤sinθ≤1,
∴0≤1+sinθ≤2. 又 log3x=1+sinθ,
∴0<1+sinθ≤2. x=31+sinθ∈(1,9].
故|x-1|+|x-9|=x-1+9-x=8,
故答案为:8