解不等式sin(x-π/4)>1/2
问题描述:
解不等式sin(x-π/4)>1/2
答
sin(x-π/4)>1/2得2kπ+π/6不懂正弦函数为周期函数,sin(x-π/4)循环周期为2π,故每个周期内都有一个范围使得sin(x-π/4)>1/2所以要加上循环
解不等式sin(x-π/4)>1/2
sin(x-π/4)>1/2得2kπ+π/6不懂正弦函数为周期函数,sin(x-π/4)循环周期为2π,故每个周期内都有一个范围使得sin(x-π/4)>1/2所以要加上循环