用因式分解 (x-1)的平方-4(1-x)+4=0

问题描述:

用因式分解 (x-1)的平方-4(1-x)+4=0

(x-1)的平方-4(1-x)+4=0
(x-1-2)的平方=0
(x-3)的平方=0
x=3

(X-1)²-4(1-X)+4=0
(1-X)²-4(1-X)+2²=0
(1-X-2)²=0
(-1-X)²=0

(x-1)^2-4(1-x)+4=0
(x-1)^2+4(x-1)+4=0
((x-1)+2)^2=0
(x+1)^2=0
x=-1

(x-1)²+4(x-1)+4=0
(x-1+2)² =0
x+1=0
x=-1