①(2y-z)²[2y(z+2y)+z²]²=②(-x-y)²(x²-xy+y²)²=
问题描述:
①(2y-z)²[2y(z+2y)+z²]²=
②(-x-y)²(x²-xy+y²)²=
答
解①原式={(2y-z)×[2y(z+2y)+z²]}²={(2y-z)[(2y)²+2yz+z²]}²=[(2y)³-z³]²=(8y³-z³)²=64y^6-16y³z³+z^6 解②原式=(x+y)²(x²-xy+y²...