36(x+2y)^2-25(x-2y)^2=?x^8-1=?(x-y+z)^2-(2x-3y+4z)^2=?36(x+2y)^2-25(x-2y)^2=x^8-1=(x-y+z)^2-(2x-3y+4z)^2=

分类: 作业答案 • 2022-02-15 00:01:04

问题描述：

36(x+2y)^2-25(x-2y)^2=?x^8-1=?(x-y+z)^2-(2x-3y+4z)^2=?
36(x+2y)^2-25(x-2y)^2=
x^8-1=
(x-y+z)^2-(2x-3y+4z)^2=

答

1、原式=（6X+12Y+5X-10Y)*(6X+12Y-5X+10Y)=(11X+2Y)*(X+22Y)
2、原式=（X-1)(X+1)(X^2+1)(X^4+1)
3、原式=（X-Y+Z+2X-3Y+4Z)(X-Y+Z-2X+3Y-4Z)=(3X-4Y+5Z)(-X+2Y-3Z)