设y(x)=arccos((1-x)/根号2),求dy答案是1/根号(1+2x-x^2)dx(|x-1|

问题描述:

设y(x)=arccos((1-x)/根号2),求dy
答案是1/根号(1+2x-x^2)dx(|x-1|

dy=根号(2/(1+2x-x^2))dx