设y(x)=arccos((1-x)/根号2),求dy答案是1/根号(1+2x-x^2)dx(|x-1|
问题描述:
设y(x)=arccos((1-x)/根号2),求dy
答案是1/根号(1+2x-x^2)dx(|x-1|
答
dy=根号(2/(1+2x-x^2))dx
设y(x)=arccos((1-x)/根号2),求dy
答案是1/根号(1+2x-x^2)dx(|x-1|
dy=根号(2/(1+2x-x^2))dx