分解公式(1)1/4x²-x+1= (2)(1-x)+(x-1)³= (3)a的2n次方-2a的2n-1次方=
问题描述:
分解公式(1)1/4x²-x+1= (2)(1-x)+(x-1)³= (3)a的2n次方-2a的2n-1次方=
答
(1)1/4x²-x+1=(x/2)²-x+1=(x/2-1)²(2)(1-x)+(x-1)³=(1-x)-(1-x)³=(1-x)[1-(1-x)²]=(1-x)[2x-x²}=x(1-x)(2-x)(3)a的2n次方-2a的2n-1次方=(3)a^2n-1次方(a-2)...