求证:log2(π)+log5(π)>2
问题描述:
求证:log2(π)+log5(π)>2
log2(π)就是以2为底,π的对数.
答
楼上的错了:搞混了logpi(2)和log2(pi)正确的做法:首先log5(pi)/log2(pi)=log5(2)>log8(2)=1/3其次pi^(4)>3^4>4^3,也就是说pi^(4/3)>4那么log2(pi)+log5(pi)=log2(pi)*[1+log5(pi)/log2(pi)]>(4/3)*log2(pi)根据上...