1/2{1/3[1/4(x+1/5-1)-6]+x}=1
问题描述：
1/2{1/3[1/4(x+1/5-1)-6]+x}=1
小括号里的是5分之x+1再-1
答
1/2{1/3[1/4(x+1/5-1)-6]+x}=1
1/3{1/4[(x+1）/5-1]-6}+x=2
1/4[(x+1）/5-1]-6+3x=6
1/4[(x+1）/5-1]=12-3x
(x+1）/5-1=48-12x
(x+1）/5=49-12x
x+1=245-60x
61x=244但是我同学说正确答案是x=65/3161x=244x=4