如果底数是3真数2的对数为A,则底数是6真数是根号24的对数是多少

问题描述:

如果底数是3真数2的对数为A,则底数是6真数是根号24的对数是多少

log(3)2=A
log(6)24
=lg24/lg6
=lg3*2^3/lg2*3
=(lg3+lg2^3)/(lg2+lg3)
=(lg3+3lg2)/(lg2+lg3) 分子分母分别除lg3
=(1+3lg2/lg3)/(lg2/lg3+1)
=(1+3log(3)2)/(log(3)2+1)
=(1+3A)/(A+1)
=(3A+1)/(A+1)