已知sina+√3*cosa=(2m+1)/(3-m),求m的取值范围,我要用分离参数法,先把m分离出来,就是化成m=……

按照分离参数法算的!令t=sina+√3cosat=sina+√3*cosa=2sin(a+π/3)t∈[-2,2]t=(2m+1)/(3-m)3t-tm=2m+1(2+t)m=3t-1m=(3t-1)/(2+t)=(3t+6-7)/(2+t)=3-7/(2+t)∵t∈[-2,2]∴2+t∈[0,4]1/(2+t)∈[1/4,+∞）7/(2+t)∈[7/...