∫(4,0)(x^2+1+sinx)dx
问题描述:
∫(4,0)(x^2+1+sinx)dx
答
∫(4,0)(x^2+1+sinx)dx =(1/3x^3 +x -cos x) |(4,0)=1/3 * 64 +4 -cos4 +cos 0
= 64/3 + 5 -cos 4