x²-x²y+xy²-x+y-y²,让我看得懂

问题描述:

x²-x²y+xy²-x+y-y²,让我看得懂

x²-x²y+xy²-x+y-y²=(x²-y²)-(x²y-xy²)-(x-y)=(x-y)(x+y)-xy(x-y)-(x-y)=(x-y)(x+y-xy-1)=-(x-y)(xy-x-y+1)=-(x-y)[(xy-x)-(y-1)]=-(x-y)[x(y-1)-(y-1)]=-(x-y)(x-1)(y-1)