若sina-cosa=1/3,0

问题描述:

若sina-cosa=1/3,0

sina-cosa=1/3两边平方(sina)^2-2sinacosa+(cosa)^2=1/9(sina)^2+(cosa)^2=1所以sin2a=2sinacosa=8/9cosa=sina-1/3带入(sina)^2+(cosa)^2=1为了方便,令x=sinax^2+(x-1/3)^2=12x^2-2x/3-8/9=09x^2-3x-4=0x=(1±√17)/...