tanα =3 求 sin²-2sinα×cosα-cos²α/4cos²-3sin²α
问题描述:
tanα =3 求 sin²-2sinα×cosα-cos²α/4cos²-3sin²α
答
(sin²-2sinα×cosα-cos²α)/(4cos²-3sin²α) 分子分母同除cos²a
=(tan2 a-2tanα-1)/(4-3tan2 a)
=(9-6-1)/(4-27)
=-2/23