4b²c²-(c²+b²)²
问题描述:
4b²c²-(c²+b²)²
答
4b²c²-(c²+b²)²=(2bc)²-(c²+b²)²=(2bc+c²+b²)[2bc-(c²+b²)]=(b+c)²[-(c²+b²-2bc)]=-(b+c)²(b-c)²
4b²c²-(c²+b²)²
4b²c²-(c²+b²)²=(2bc)²-(c²+b²)²=(2bc+c²+b²)[2bc-(c²+b²)]=(b+c)²[-(c²+b²-2bc)]=-(b+c)²(b-c)²