已知数列{an}的各项均为正数,前n项和为Sn,且Sn=an(an+1)/2,设bn=1/2Sn,Tn=b1+b2+…+bn,求Tn
问题描述：
已知数列{an}的各项均为正数,前n项和为Sn,且Sn=an(an+1)/2,设bn=1/2Sn,Tn=b1+b2+…+bn,求Tn
答
sn=an(an+1)/2---------------1s(n-1)=a(n-1) (a(n-1)+1)/2-----------------21减2得an = an(an+1)/2-a(n-1) (a(n-1)+1)/2an^2-an-a^2(n-1) -a(n-1) =0(an-a(n-1))(an+a(n-1))-(an+a(n-1))=0(an-a(n-1)-1)(an+a(n-1)...