若1/x-1/y=3,则2x+3xy-2y/x-xy-y的值为多少
问题描述：
若1/x-1/y=3,则2x+3xy-2y/x-xy-y的值为多少
答
1/x-1/y=3
则 y-x=3xy
2x+3xy-2y/x-xy-y
=[2(x-y)+3xy]/(x-y-xy)
=(-3xy)/(-4xy)
=3/4
答
若1/x-1/y=3,
则2x+3xy-2y/x-xy-y
=(2/y+3-2/x)/(1/y-1-1/x)
=(3-2×3)/(-1-3)
=-3/(-4)
=3/4;
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