x+y=9 (100x+y)-(10y+x)=3[(10y+x)-(10x+y)]
问题描述:
x+y=9 (100x+y)-(10y+x)=3[(10y+x)-(10x+y)]
x+y=9
(100x+y)-(10y+x)=3[(10y+x)-(10x+y)]
是二元一次方程啊
答
x+y=9(100x+y)-(10y+x)=3[(10y+x)-(10x+y)]
解得x=2y=7