f(x)=asinx+btanx+1,f(5)=7,则f(2010π-5)=
问题描述:
f(x)=asinx+btanx+1,f(5)=7,则f(2010π-5)=
答
f(x)=asinx+btanx+1,f(5)=7,
则f(2010π-5)
=-asin5-btan5+1
=-asin5-btan5+1
=-asin5-btan5+1
=-(asin5+btan5+1)+2
=-f(5)+2
=-7+2=-5