函数y=cosx平方+sinxcosx的最小正周期是
问题描述：
函数y=cosx平方+sinxcosx的最小正周期是
答
y=(1+cos2x)/2+(sin2x)/2
=1/2(sin2x+cos2x)+1/2
=√2/2(√2/2*sin2x+√2/2cos2x)+1/2
=√2/2(sin2xcosπ/4+cos2xsinπ/4)+1/2
=√2/2sin(2x+π/4)+1/2
所以 T=2π/2=π