6/（x+1）=(x+5)/[x(x+1)] (3-x)/(x-4)+1/(4-x)=1 2/(1+x)-3/(1-x)=6/(x*x-1) (2x-3)/(x-1)=(2x-4)/(2x+3)

应该是分成4个题吧
[1] 6/（x+1）=(x+5)/[x(x+1)]
[2] (3-x)/(x-4)+1/(4-x)=1
[3] 2/(1+x)-3/(1-x)=6/(x*x-1)
[4] (2x-3)/(x-1)=(2x-4)/(2x+3)
分别解出
[1] 6/（x+1）=(x+5)/[x(x+1)] 简化6x=x+5, x=1
[2] (3-x)/(x-4)+1/(4-x)=1 简化3-x-1=x-4, x=3
[3] 2/(1+x)-3/(1-x)=6/(x*x-1)简化2(x-1)+3(x+1)=6, x=1，依题意x=1分母为零，所以此题无解
[4] (2x-3)/(x-1)=(2x-4)/(2x+3)简化(2x-3)(2x+3)=(2x-4)(x-1), 2x*x+6x-13=0,
x=[-3±(35)^0.5]/2

6/（x+1）=(x+5)/[x(x+1)]6x=(x+5) (两边同乘x(x+1))5x=5 (合并同类项)x=1(3-x)/(x-4)+1/(4-x)=1 (3-x)-1=(x-4) (两边同乘(x-4))2x=6 (合并同类项)x=3 2/(1+x)-3/(1-x)=6/(x²-1)2/(1+x)-3/(1-x)=6/[(x-1)(1+x)]...