求方程组①x1+x2+2x3-3x4=0;②3x1+2x2-x3+2x4=0;③x1-5x3+8x4=0;的通解.
问题描述:
求方程组①x1+x2+2x3-3x4=0;②3x1+2x2-x3+2x4=0;③x1-5x3+8x4=0;的通解.
答
x1 = 5 x3 - 8 x4
x2 = -7 x3 + 11 x4
x3 x4为*变元,可以随便从R上取