函数Y=sin^2(x/2)-cos^2(x/2)的最小正周期怎么计算?
问题描述:
函数Y=sin^2(x/2)-cos^2(x/2)的最小正周期怎么计算?
答
根据cosx=-(sin^2(x/2)-cos^2(x/2)) T=2PAI
函数Y=sin^2(x/2)-cos^2(x/2)的最小正周期怎么计算?
根据cosx=-(sin^2(x/2)-cos^2(x/2)) T=2PAI