因式分解：2a方+2b方-4ab-2
问题描述：
因式分解：2a方+2b方-4ab-2
答
原式=2（a-b）^2-2
=2[(a-b)^2-1]
=2(a-b+1)(a-b-1)
答
2(a²-2ab+b²-1)
=2[(a-b)²-1]
=2(a-b+1)(a-b-1)
答
答：
2a^2+2b^2-4ab-2
=2(a^2-2ab+b^2)-2*1
=2(a-b)^2-2*1^2
=2(a-b+1)(a-b-1)
答
解
2a²+2b²-4ab-2
=2(a²-2ab+b²)-2
=2(a-b)²-2
=2[(a-b)²-1]
=2(a-b-1)(a-b+1)