-1/42÷(1/6-2/7+2/3-3/14)不要只写什么"分子分母乘42"之类的!

问题描述:

-1/42÷(1/6-2/7+2/3-3/14)
不要只写什么"分子分母乘42"之类的!

-1/42÷(1/6-2/7+2/3-3/14)
=-1/42÷[1/6+2/3-(2/7+3/14)]
=-1/42÷(5/6-7/14)
=-1/42÷1/3
=-1/14

答:
-1/42÷(1/6-2/7+2/3-3/14)
=-1/[42×(1/6-2/7+2/3-3/14)]
=-1/(42/6-42*2/7+42*2/3-42*3/14)
=-1/(7-12+28-9)
=-1/14
回答完毕.