数列裂项求和sn=1/(1+2)+1/(1+2+3)+~+1/(1+2+3+~+n)
问题描述:
数列裂项求和sn=1/(1+2)+1/(1+2+3)+~+1/(1+2+3+~+n)
答
1+2+……+n=n(n+1)/2
则原式=2×[1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+......+1/n-1/(n+1)]
=2×[1/2-1/(n+1)]
=1-2/(n+1)
答
原式=2×[1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+.+1/n-1/(n+1)]
=2×[1/2-1/(n+1)]
=1-2/(n+1)