(b-c)^2=(c-a)^2=(a-b)^2 求证:a=b=c (b-c)^2-(c-a)^2=0 (b-c+c-a)(b-c-c+ why(a-c)(3c-3a)=03(a-c)^2=0a-c=0why得不出来
问题描述:
(b-c)^2=(c-a)^2=(a-b)^2 求证:a=b=c (b-c)^2-(c-a)^2=0 (b-c+c-a)(b-c-c+ why
(a-c)(3c-3a)=0
3(a-c)^2=0
a-c=0
why得不出来
答