化简求值cos(-11π/3)=_,tan(-1035°)=_
问题描述：
化简求值cos(-11π/3)=_,tan(-1035°)=_
答
cos(-11π/3)=1/2 tan(-1035°)=tan(-3x360°+45)=tan45°=1
答
cos(-11兀/3+4兀)=cos(兀/3)=0.5
tan(-1035°)=tan(-3x360°+45)=tan45°=1