已知x+y=-3 求(2x²+xy+3y²)-(x²-xy+2y²)的值
问题描述:
已知x+y=-3 求(2x²+xy+3y²)-(x²-xy+2y²)的值
答
(2x²+xy+3y²)-(x²-xy+2y²)
=x²+2xy+y²
=(x+y)²
=(-3)²
=9
答
(2x²+xy+3y²)-(x²-xy+2y²)
=x^2+2xy+y^2
=(x+y)^2
=(-3)^2
=9
答
(2x²+xy+3y²)-(x²-xy+2y²)
=2x²+xy+3y²-x²+xy-2y²
=x²+2xy+y²
=(x+y)²
=3²
=9
答
已知x+y=-3 求(2x²+xy+3y²)-(x²-xy+2y²)的值
原式=x²+2xy+y²=(x+y)²=(-3)²=9