x+y)(x-y)+(x-y)^2-(6x^2y-2xy^2)/2y,其中x=-2,y=1/3
问题描述:
x+y)(x-y)+(x-y)^2-(6x^2y-2xy^2)/2y,其中x=-2,y=1/3
答
x+y)(x-y)+(x-y)^2-(6x^2y-2xy^2)/2y
=x^2-y^2+x^2-2xy+y^2-3x^2+xy
=-x^2-xy
=-(-2)^2-(-2)(1/3)
=-4+2/3
=-10/3