已知△ABC和△AED是等边三角形,BD=CE,求证∠ECA=∠DBA

问题描述:

已知△ABC和△AED是等边三角形,BD=CE,求证∠ECA=∠DBA

∠BAD = ∠BAC + ∠CAD ∠CAE = ∠EAD + ∠CAD ∠BAC = ∠EAD ∠BAD = ∠CAE AC=AB ∠BAD = ∠CAE BD=CE △ACE 全等于 △ABD ∠ECA=∠DBA