若2x+1的绝对值+根号y+2=0,则立方根号5x^3-y^2=?
问题描述:
若2x+1的绝对值+根号y+2=0,则立方根号5x^3-y^2=?
答
2x+1的绝对值+根号y+2=0,
则2x+1=0y+2=0
则x= -1/2y= -2
5x^3-y^2
=5×(-1/2)³-(-2)²
=5/8-4
= -27/8