[9n^2+3n)/(3n-1)^2]^n的极限是多少?
问题描述：
[9n^2+3n)/(3n-1)^2]^n的极限是多少?
n趋向无穷大
快来人啊
答
(9n^2+3n)/(3n-1)^2=(9n^2+3n)/(9n^2-6n+1)=(9+3/n)/(9-6/n+1/n^2)
lim[9n^2+3n)/(3n-1)^2]^n=lim[(9+3/n)/(9-6/n+1/n^2)]^n
=1