请问f(x)=根号3sin(wx+φ)-cos(wx+φ)=2Sin(wx+φ-π/6)如何化简?
问题描述：
请问f(x)=根号3sin(wx+φ)-cos(wx+φ)=2Sin(wx+φ-π/6)如何化简?
答
f(x)=根号3sin(wx+φ)-cos(wx+φ)=2[根号3sin(wx+φ)/2-cos(wx+φ)/2]=2[sin(wx+φ)cos(π/6)-cos(wx+φ)sin(π/6)]=2Sin(wx+φ-π/6)