要使(ax2-3x)(x2-2x-1)的展开式中不含x3项,则a=_.
问题描述:
要使(ax2-3x)(x2-2x-1)的展开式中不含x3项,则a=______.
答
∵(ax2-3x)(x2-2x-1),
=ax4-2ax3-ax2-3x3+6x2+3x,
=ax4-(2a+3)x3-(a-6)x2+3x,
又∵展开式中不含x3项
∴2a+3=0,
解得a=-
.3 2