四.9.数列知识求助,
问题描述：
四.9.数列知识求助,
数列1/(2乘以5）,1/（5乘以8）,1/（8乘以11）,……的前n项和Sn为?我知道用拆项求和法,答案是n/（6n+4）,我拆不出来啊,
答
Sn=(1/2x5)+(1/5x8)+(1/8x11)+…+(1/(3n-1)(3n+2))
=1/3[(1/2-1/5)+(1/5-1/8)+(1/8-1/11)+…+(1/(3n-1)-1/(3n+2))]
=1/3(1/2-1/(3n+2))
=n/(6n+4)