(1/2)^(3+log以2为底,真数为3的对数)=

问题描述:

(1/2)^(3+log以2为底,真数为3的对数)=

=(1/2)^3×(1/2)^[log2(3)]
=1/8×3
=3/8(1/2)^[log2(3)]=3为什么?怎么算的?哦,错了是=1/2^[log2(3)]=1/3所以原式=1/24公式a^[loga(N)]=N