解下列方程①根号3x+根号2=根号2x+根号3②根号2(根号2-x)+x=根号2
问题描述:
解下列方程①根号3x+根号2=根号2x+根号3②根号2(根号2-x)+x=根号2
答
①根号3x+根号2=根号2x+根号3
根号3x-根号2x=根号3-根号2 (两边平方有)
3x+2x-2根号6*x=5-2根号6
x=(5-2根号6)/(5-2根号6)=1
②根号2(根号2-x)+x=根号2
2-根号2*x+x=根号2
(1-根号2)x=根号2-2=根号2(1-根号2)
x=根号2