cosα+sinα=-1/3,则sin2α等于?

问题描述:

cosα+sinα=-1/3,则sin2α等于?

cosα+sinα=-1/3,平方
(cosα+sinα)^2=1/9
(cosα)^2+2sinαcosα+(sinα)^2=1/9
1+2sinαcosα=1/9
2sinαcosα=-8/9
sin2α=-8/9