求函数y=√2sin(2x-π/4)的单调递减区间
问题描述:
求函数y=√2sin(2x-π/4)的单调递减区间
答
y=2sin(2x+π/4)+1 y=sinx单调递减区间是 【2kπ-π/2,2kπ+π/2】所以2kπ-π/2
求函数y=√2sin(2x-π/4)的单调递减区间
y=2sin(2x+π/4)+1 y=sinx单调递减区间是 【2kπ-π/2,2kπ+π/2】所以2kπ-π/2